9x^2<25

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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9x²<25

Solution

−53 <x<53

Interval Notation

(−53 , 53 )

Decimal

−1.66666…<x<1.66666…

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Solution steps

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9x²<25

Divide both sides by 9

x²<259

For uⁿ < a, if n is even then −ⁿ√a < u < ⁿ√a

−√259 <x<√259

√259 =53

−53 <x<53

Number Line

−53 <x<53

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

9x^2<25

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