f(x)=(x+1)(x^2-2x+4)

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f(x)=(3x²−2)+(4x+2)

Solution

Domain: −∞ <x<∞

Range: f(x)≥ −43

X Intercepts: (0, 0), (−43 , 0), Y Intercepts: (0, 0)

Vertex: Minimum (−23 , −43 )

Inverse: −2+√3x+43 , −√3x+4+23

Interval Notation

Domain: (−∞ , ∞ )

Range: [−43 , ∞ )

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Domain of 3x²−2+4x+2 : −∞ <x<∞

Range of 3x²−2+4x+2: f(x)≥ −43

Axis interception points of 3x²−2+4x+2: X Intercepts: (0, 0), (−43 , 0), Y Intercepts: (0, 0)

Vertex of 3x²−2+4x+2: Minimum (−23 , −43 )

Inverse of 3x²−2+4x+2: −2+√3x+43 , −√3x+4+23

Solve instead

ddx ((3x²−2)+(4x+2))

parity 3x²−2+4x+2

symmetry 3x²−2+4x+2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

f(x)=(x+1)(x^2-2x+4)

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