f(x)=tan^2(x)+1

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify solve for inverse tangent line

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f(x)=tan²(x)+1

Solution

Period: π

Domain: πn≤ x<π2 +πn or π2 +πn<x<π+πn

Range: f(x)≥ 1

Y Intercepts: (0, 1)

Asymptotes: Vertical x=π2 +πn

Extreme Points: Minimum(πn, 1)

Interval Notation

Domain: [πn, π2 +πn)∪(π2 +πn, π+πn)

Range: [1, ∞ )

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Periodicity of tan²(x)+1: π

Domain of tan²(x)+1 : πn≤ x<π2 +πn or π2 +πn<x<π+πn

Range of tan²(x)+1: f(x)≥ 1

Axis interception points of tan²(x)+1: Y Intercepts: (0, 1)

Asymptotes of tan²(x)+1: Vertical: x=π2 +πn

Extreme Points of tan²(x)+1: Minimum(πn, 1)

Solve instead

ddx (tan²(x)+1)

inverse tan²(x)+1

parity tan²(x)+1

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+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

f(x)=tan^2(x)+1

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