Hi, ask a question about (
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1√6 | 1√6 | 2√6 |
1√2 | −1√2 | 0 |
−1√3 | −1√3 | 1√3 |
−2 | 1 | 2 |
1 | −2 | 2 |
2 | 2 | 1 |
1√6 | 1√6 | 2√6 |
1√2 | −1√2 | 0 |
−1√3 | −1√3 | 1√3 |
step-by-step
\begin{pmatrix} \frac{1}{\sqrt{6}} & \frac{1}{\sqrt{6}} & \frac{2}{\sqrt{6}} \\ \frac{1}{\sqrt{2}} &-\frac{1}{\sqrt{2}} & 0 \\ -\frac{1}{\sqrt{3}} &-\frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}}\end{pmatrix}\begin{pmatrix} -2 & 1 & 2 \\ 1 &-2 & 2 \\ 2 & 2 & 1\end{pmatrix}\begin{pmatrix} \frac{1}{\sqrt{6}} & \frac{1}{\sqrt{6}} & \frac{2}{\sqrt{6}} \\ \frac{1}{\sqrt{2}} &-\frac{1}{\sqrt{2}} & 0 \\ -\frac{1}{\sqrt{3}} &-\frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}}\end{pmatrix}^{T}
en