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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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Steps Examples

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midpoint (0.25, 4), (−0.9, −2)

Solution

(−0.325, 1)

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Solution steps

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Midpoint of (x₁, y₁), (x₂, y₂): (x₂+x₁2 , y₂+y₁2 )

(x₁, y₁)=(0.25, 4), (x₂, y₂)=(−0.9, −2)

=(−0.9+0.252 , −2+42 )

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=(−0.325, 1)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

1+	+2+
3+	+4

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