((2ab^{^3})^{^{-1}})/(20(2^{^{-1)}ba^5)^{^2}}*((4ab^{^{-1}})/(5b))^{^{-2}}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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simplify (2ab³)⁻¹20· (2⁻¹· ba⁵)² · (4ab⁻¹5b )⁻²

Solution

532a¹³b

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Solution steps

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(2ab³)⁻¹20(2⁻¹ba⁵)² (4ab⁻¹5b )⁻²

Simplify (4ab⁻¹5b )⁻²: 25b⁴16a²

=(2ab³)⁻¹20(2⁻¹ba⁵)² · 25b⁴16a²

Cancel (2ab³)⁻¹20(2⁻¹ba⁵)² : 1ab³· 10a¹⁰b²

=1ab³· 10a¹⁰b² · 25b⁴16a²

Apply the fraction rule: ab · cd =a · cb · d

=1· 25b⁴ab³· 10a¹⁰b²· 16a²

Multiply the numbers: 1· 25=25

=25b⁴ab³· 10a¹⁰b²· 16a²

Factor the number: 25=5· 5

=5· 5b⁴ab³· 10a¹⁰b²· 16a²

Factor the number: 10=5· 2

=5· 5b⁴ab³· 5· 2a¹⁰b²· 16a²

Cancel the common factor: 5

=5b⁴ab³· 2a¹⁰b²· 16a²

Simplify b⁴b³ : b

=5ba· 2a¹⁰b²· 16a²

Simplify bb² : 1b

=5a· 2a¹⁰b· 16a²

Simplify a· 2a¹⁰b· 16a²: a¹³· 32b

=5a¹³· 32b

=532a¹³b

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

((2ab^{^3})^{^{-1}})/(20*(2^{^{-1)}*ba^5)^{^2}}*((4ab^{^{-1}})/(5b))^{^{-2}}

Solution

Solution steps

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((2ab^{^3})^{^{-1}})/(20(2^{^{-1)}ba^5)^{^2}}*((4ab^{^{-1}})/(5b))^{^{-2}}