(\partial)/(\partialx)(ln(xy))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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eccentricity 16x²+25y²=100

Solution

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0.6

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Ellipse eccentricity

The eccentricity is a measure of how much the ellipse deviates from a circle.
For an ellipse with major axis parallel to the x-axis, the eccentricity is√a²−b²a

=√a²−b²a

Calculate ellipse properties

16x²+25y²=100: Ellipse with center (h, k)=(0, 0), a=52 , b=2

=√(52 )²−2²52

√(52 )²−2²52 =35

=35

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(\partial)/(\partialx)(ln(xy))

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