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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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Steps Examples

Generated by AI

solve for x, x=10cdofrac5⁵2cdotleft(frac2left(2cdot−5right)⁵5cdot5cdot2cdofrac105right)cdofracleft(10²cdot5right)2+2left(5+5right)cdotleft(frac510+frac22right)⁵−left(2cdot5right)

Solution

x=656250000000e³c¹¹a⁴l³d⁷i²o⁷f⁷r⁶t⁹g²h²(2cdot−5irtgh)⁵+2e²cl²dof²t³(5+5irtgh)(510cafr+22caifr²tgh)⁵−10ecldiofrt³gh

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Solution steps

One step at a time

(

1√6	1√6	2√6
1√2	−1√2	0
−1√3	−1√3	1√3

)(

−2	1	2
1	−2	2
2	2	1

)(

1√6	1√6	2√6
1√2	−1√2	0
−1√3	−1√3	1√3

)^T

(

1√6	1√6	2√6
1√2	−1√2	0
−1√3	−1√3	1√3

)^T=(

1√6	1√2	−1√3
1√6	−1√2	−1√3
2√6	0	1√3

)

1√6	1√6	2√6
1√2	−1√2	0
−1√3	−1√3	1√3

)(

−2	1	2
1	−2	2
2	2	1

)(

1√6	1√2	−1√3
1√6	−1√2	−1√3
2√6	0	1√3

)

(

1√6	1√6	2√6
1√2	−1√2	0
−1√3	−1√3	1√3

)(

−2	1	2
1	−2	2
2	2	1

)=(

√32	√32	√6
−3√2	3√2	0
√3	√3	−√3

)

√32	√32	√6
−3√2	3√2	0
√3	√3	−√3

)(

1√6	1√2	−1√3
1√6	−1√2	−1√3
2√6	0	1√3

)

(

√32	√32	√6
−3√2	3√2	0
√3	√3	−√3

)(

1√6	1√2	−1√3
1√6	−1√2	−1√3
2√6	0	1√3

)=(

3	0	0
0	−3	0
0	0	−3

)

3	0	0
0	−3	0
0	0	−3

)

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Hi, ask a question about (

12	−12	0
12	12	0
12	−12	1

)(

1	0	0
0	−1	0
0	0	0

)(

12	12	12
−12	12	−12
0	0	1

)

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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Solution

Solution steps

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