вершины 25x^2+4y^2+100x-40y=400

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

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simplify solve for inverse tangent line

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vertices (x−1)²9 +y²5 =100

Solution

(31, 0), (−29, 0)

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Ellipse vertices

The vertices are the two points on the ellipse that intersect the major axis
For an ellipse with major axis parallel to the x-axis, the vertices are (h+a, k), (h−a, k)

(h+a, k), (h−a, k)

Calculate ellipse properties

(x−1)²9 +y²5 =100: Ellipse with center (h, k)=(1, 0), a=30, b=10√5

(1+30, 0), (1−30, 0)

Refine

(31, 0), (−29, 0)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

вершины 25x^2+4y^2+100x-40y=400

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