критические точки y= x/(x^2-6x+8)

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critical points y=xx²−6x+8

Solution

x=−2√2, x=2√2

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xx²−6x+8

Critical point definition

Critical points are points where the function is defined and its derivative is zero or undefined

Find where f ′(x) is equal to zero or undefined

x=−2√2, x=2√2, x=2, x=4

Identify critical points not in f(x) domain

Domain of xx²−6x+8 : x<2 or 2<x<4 or x>4

xx²−6x+8 is not defined at x=2, x=4, therefore:

x=−2√2, x=2√2

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domain xx²−6x+8

range xx²−6x+8

inverse xx²−6x+8

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

критические точки y= x/(x^2-6x+8)

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