площадь r^2=16sin(2theta)

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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area r²=16sin(2θ)

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Area under a polar curve definition

The area under a polar curve given by r = f(θ) between the radial lines θ = a and θ = b is
A=12 ∫_a^br²dθ

Identify the interval: (0, π2 ), (π, 3π2 )

Apply the area formula: 12 · ∫₀^π216sin(2θ)dθ+12 · ∫_π^3π216sin(2θ)dθ

Solve 12 ∫₀^π216sin(2θ)dθ+12 ∫_π^3π216sin(2θ)dθ: 16

=16

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
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площадь r^2=16sin(2theta)

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