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synthetic division 4x3−7x2−11x+54x+5
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Solution
x2−3x+1
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Solution steps
Solve by:
One step at a time
4x3−7x2−11x+54x+5
Factor out coefficient of the denominator
4x+5=4·(x+54)
4x3−7x2−11x+54(x+54)
Coefficients of the numerator polynom
4−7−115
Find the zeros of the denominator:x=−54
Write the problem in synthetic division format
−54¦4−7−115
¦
Carry down the leading coefficient, unchanged, to below the division symbol
−54¦4−7−115
¦
4
Multiply the carry-down value by the zero of the denominator, and carry the result up into the next column:
4(−54)=−5
−54¦4−7−115
¦−5
4
Add down the column:
−7−5=−12
−54¦4−7−115
¦−5
4−12
Multiply the carry-down value by the zero of the denominator, and carry the result up into the next column:
(−12)(−54)=15
−54¦4−7−115
¦−515
4−12
Add down the column:
−11+15=4
−54¦4−7−115
¦−515
4−124
Multiply the carry-down value by the zero of the denominator, and carry the result up into the next column: