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implicit derivative dydx , 2(x²+y²)²=25(x²−y²)

Solution

dydx =x(25−4x²−4y²)y(4x²+4y²+25)

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2(x²+y²)²=25(x²−y²)

Treat y as y(x)

Differentiate both sides: 4(x²+y²)(2x+2ydydx )=25(2x−2ydydx )

Isolate dydx : dydx =x(25−4x²−4y²)y(4x²+4y²+25)

dydx =x(25−4x²−4y²)y(4x²+4y²+25)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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