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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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Steps Examples

Generated by AI

angle (1, 1)

Solution

π4

Degrees

45^◦

Decimal

0.78539…

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Solution steps

One step at a time

Angle from the x-axis

The angle between a vector, (

a

b

) and the positive x−axis depends on the quadrant the point is in
First Quadrant:    θ=arctan(ba )
Second Quadrant:    θ=π−arctan(|ba |)
Third Quadrant:    θ=arctan(|ba |)−π
Fourth Quadrant:    θ=−arctan(|ba |)

The quadrant of (1, 1): 1

The angle between (1, 1) and the x-axis is

arctan(11 )

Compute arctan(θ): arctan(11 )=π4

=π4

Examples

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