ラプラス変換 xcos(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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laplace transform xcos(x)

Solution

−−s²+1(s²+1)²

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Solution steps

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L{xcos(x)}

Use Laplace Transform table: L{t^kf(t)}=(−1)^kd^kds^k (L{f(t)})

For xcos(x): f(x)=cos(x), k=1

=(−1)¹dds (L{cos(x)})

L{cos(x)}: ss²+1

dds (ss²+1 )=−s²+1(s²+1)²

=(−1)¹−s²+1(s²+1)²

=−−s²+1(s²+1)²

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inverse laplace xcos(x)

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

ラプラス変換 xcos(x)

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