求解 x,cos(xy)=sin(x+y)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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^□√☐

□□

log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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solve for x, cos(xy)=sin(x+y)

Solution

x=π+4πn−2y2(1+y) , x=π+4πn−2y2(1−y)

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Solution steps

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cos(xy)=sin(x+y)

Rewrite using trig identities

cos(xy)=sin(π2 −xy)

Apply trig inverse properties

x+y=π2 −xy+2πn, x+y=π−(π2 −xy)+2πn

x+y=π2 −xy+2πn : x=π+4πn−2y2(1+y) ; y≠ −1

x+y=π−(π2 −xy)+2πn : x=π+4πn−2y2(1−y) ; y≠ 1

x=π+4πn−2y2(1+y) , x=π+4πn−2y2(1−y)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

求解 x,cos(xy)=sin(x+y)

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