逆ラプラス cos^3(t)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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midpoint (−9, 4), (−132 , 6)

Solution

(−314 , 5)

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Midpoint of (x₁, y₁), (x₂, y₂): (x₂+x₁2 , y₂+y₁2 )

(x₁, y₁)=(−9, 4), (x₂, y₂)=(−132 , 6)

=(−132 −92 , 6+42 )

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=(−314 , 5)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

逆ラプラス cos^3(t)

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