領域 sin(5x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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range cos(2t)

Solution

−1≤ f(t)≤ 1

Interval Notation

[−1, 1]

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Function range definition

The set of values of the dependent variable for which a function is defined

The range of the basic cos function is −1≤ cos(2t)≤ 1

−1≤ cos(2t)≤ 1

Therefore the range is

−1≤ f(t)≤ 1

Solve instead

domain cos(2t)

periodicity cos(2t)

amplitude cos(2t)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

領域 sin(5x)

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