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gram-schmidt (
3
4
),(
4
4
)
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Solution
e1=(
35
45
),e2=(
45
−35
)
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One step at a time
v1=(
3
4
),v2=(
4
4
)
Gram-Schmidt process
For a finite, linearly independent set of vectors v1,…vk,uk=vk−∑j=1k−1projuj(vk), where proju(v)=v·u|u|2u. The normalized vector is ek=uk|uk|