증명 (1-sin(x))/(1+sin(x))=(sec(x)-tan(x))^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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sequence type a_n+1=−3a_n, a₁=8

Solution

geometric sequence: r=−3, a_n=8(−3)ⁿ⁻¹

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Solution steps

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ddx ((2x³+11x²+5x)(2x²+x) )

Simplify (2x³+11x²+5x)(2x²+x) : x+5

=ddx (x+5)

Apply the Sum/Difference Rule: (f±g)′=f ′±g′

=dxdx +ddx (5)

dxdx =1

ddx (5)=0

=1+0

Simplify

Solve instead

first term a_n+1=−3a_n, a₁=8

nth term a_n+1=−3a_n, a₁=8

next term a_n+1=−3a_n, a₁=8

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

증명 (1-sin(x))/(1+sin(x))=(sec(x)-tan(x))^2

Solution

Solution steps

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