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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

합리적인 루트 3x^3-5x^2+5x-2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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rational roots 3x³−5x²+5x−2

Solution

x=23

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Solution steps

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3x³−5x²+5x−2

Rational root theorem definition

For a polynomial equation with integer coefficients: a_nxⁿ+a_n−1xⁿ⁻¹+…+a₀
If a₀ and a_n are integers, then if there is a rational solution
it could be found by checking all the numbers produced for ± dividers of a₀ dividers of a_n

a₀=2,     a_n=3
The dividers of a₀:    1, 2,     The dividers of a_n:    1, 3
The following rational numbers are candidate roots:     ± 1, 21, 3

Validate the roots by plugging them into 3x³−5x²+5x−2=0: x=23

x=23

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