2c-3=2(6-c)+7c

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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2c−3=2(6−c)+7c

Solution

c=−5

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2c−3=2(6−c)+7c

Expand 2(6−c): 12−2c

2c−3=12−2c+7c

Add similar elements: −2c+7c=5c

2c−3=12+5c

Move 3 to the right side

2c=5c+15

Move 5c to the left side

−3c=15

Divide both sides by −3

c=−5

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

2c-3=2(6-c)+7c

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