4|x+10|>=8

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simplify solve for inverse tangent line

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4|x+10|≥ 8

Solution

x≤ −12 or x≥ −8

Interval Notation

(−∞ , −12]∪ [−8, ∞ )

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Solution steps

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4|x+10|≥ 8

Divide both sides by 4

|x+10|≥ 2

Apply absolute rule: If |u| ≥ a, a > 0 then u ≤ −a or u ≥ a

x+10≤ −2 or x+10≥ 2

x≤ −12 or x≥ −8

Number Line

x≤ −12 or x≥ −8

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

4|x+10|>=8

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