achse y=x^2+2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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foci y=3x· x

Solution

(0, 112 )

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Solution steps

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∫ e^3xdx

Apply Integration By Parts: e^3xx−∫ e^3x· 3xdx

=e^3xx−∫ e^3x· 3xdx

∫ e^3x· 3xdx=e^3xx−13 e^3x

=e^3xx−(e^3xx−13 e^3x)

Simplify

=13 e^3x

Add a constant to the solution

=13 e^3x+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

achse y=x^2+2

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