amplitude of 2cos^2(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx (3x²(x³−2x))

Solution

3(5x⁴−6x²)

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ddx (3x²(x³−2x))

Take the constant out: (a·f)′=a·f ′

=3ddx (x²(x³−2x))

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=x², g=x³−2x

=3(ddx (x²)(x³−2x)+ddx (x³−2x)x²)

ddx (x²)=2x

ddx (x³−2x)=3x²−2

=3(2x(x³−2x)+(3x²−2)x²)

Expand 2x(x³−2x)+(3x²−2)x²: 5x⁴−6x²

=3(5x⁴−6x²)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

amplitude of 2cos^2(x)

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