axis 4x^2-9y^2-48x-72y+108=0

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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vertices 4x²−9y²−48x−72y+108=0

Solution

(6, −4+2√3), (6, −4−2√3)

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Hyperbola vertices

The vertices (h, k+a), (h, k−a) are the two bending points of the hyperbola with center (h, k) and semi-axis a, b.

(h, k+a), (h, k−a)

Calculate Hyperbola properties

4x²−9y²−48x−72y+108=0: Up-down Hyperbola with (h, k)=(6, −4), a=2√3, b=3√3

(6, −4+2√3), (6, −4−2√3)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

axis 4x^2-9y^2-48x-72y+108=0

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