diameter (x-4)^2+(y+2)^2=25

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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implicit derivative dydx , x³+y³=6xy

Solution

dydx =2y−x²y²−2x

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ddx (11x+18x¹⁴−8x )

Apply the Quotient Rule: (fg )^′=f ′·g−g′·fg²

=ddx (11x+18)(x¹⁴−8x)−ddx (x¹⁴−8x)(11x+18)(x¹⁴−8x)²

ddx (11x+18)=11

ddx (x¹⁴−8x)=14x¹³−8

=11(x¹⁴−8x)−(14x¹³−8)(11x+18)(x¹⁴−8x)²

Expand 11(x¹⁴−8x)−(14x¹³−8)(11x+18): −143x¹⁴−252x¹³+144

=−143x¹⁴−252x¹³+144(x¹⁴−8x)²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

diameter (x-4)^2+(y+2)^2=25

Solution

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