eje 9x^2+4y^2=1

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axis 9x²+4y²=1

Solution

semi−major axis b=12 , semi−minor axis a=13

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9x²+4y²=1

Ellipse standard equation

(x−h)²a² +(y−k)²b² =1 is the ellipse standard equation
with center (h, k) and a, b are the semi-major and semi-minor axes

Rewrite 9x²+4y²=1 in the form of the standard ellipse equation

(x−0)²(13 )² +(y−0)²(12 )² =1

Therefore ellipse properties are:

(h, k)=(0, 0), a=13 , b=12

b>a therefore b is semi-major axis and a is semi-minor axis

Ellipse with center (h, k)=(0, 0), b=12 , a=13

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

eje 9x^2+4y^2=1

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