expand (2-k)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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linear dxdt =5x−3

Solution

x=35 +c₁e^5t

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Solution steps

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∫ 6x· 2^xdx

Take the constant out: ∫a·f(x)dx=a·∫f(x)dx

=6· ∫ x· 2^xdx

Apply Integration By Parts: 2^xxln(2) −∫ 2^xln(2) dx

=6(2^xxln(2) −∫ 2^xln(2) dx)

∫ 2^xln(2) dx=2^xln²(2)

=6(2^xxln(2) −2^xln²(2) )

Add a constant to the solution

=6(2^xxln(2) −2^xln²(2) )+C

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

expand (2-k)^2

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