foci ax^2=bycos(arcsin(a/b))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

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□□

log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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simplify solve for inverse tangent line

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foci ax²=bycos(arcsin(ab ))

Solution

(0, bcos(arcsin(ab ))4a )

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Parabola Focus

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (the directrix)

Parabola standard equation

4p(y−k)=(x−h)² is the standard equation for an up-down facing parabola with vertex at (h, k),
and a focal length |p|

Rewrite ax²=bycos(arcsin(ab )) in the standard form: 4· bcos(arcsin(ab ))4a (y−0)=(x−0)²

(h, k)=(0, 0), p=bcos(arcsin(ab ))4a

Parabola is symmetric around the y-axis and so the focus lies a distance p from the center (0, 0) along the y-axis

(0, 0+p)

=(0, 0+bcos(arcsin(ab ))4a )

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(0, bcos(arcsin(ab ))4a )

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

foci ax^2=bycos(arcsin(a/b))

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