foki -((y-3)^2}{25}+\frac{(x+2)^2)/9 =1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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foci −(y−3)²25 +(x+2)²9 =1

Solution

(−2+√34, 3), (−2−√34, 3)

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Hyperbola Foci

For a right-left facing hyperbola, the Foci (focus points) are defined as (h+c, k), (h−c, k),
where c=√a²+b² is the distance from the center (h, k) to a focus

(h+c, k), (h−c, k)

Calculate Hyperbola properties

−(y−3)²25 +(x+2)²9 =1: Right-left Hyperbola with (h, k)=(−2, 3), a=3, b=5

(−2+c, 3), (−2−c, 3)

Compute c:

c=√3²+5²: √34

(−2+√34, 3), (−2−√34, 3)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

foki -((y-3)^2}{25}+\frac{(x+2)^2)/9 =1

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