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implicit derivative d2ydx2,y=sin(3x+4y)
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Solution
d2ydx2=−9sin(3x+4y)(1−4cos(3x+4y))3
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Solve by:
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y=sin(3x+4y)
Treat y as y(x)
Implicit Derivative dydx of y=sin(3x+4y):3cos(3x+4y)1−4cos(3x+4y)
dydx=3cos(3x+4y)1−4cos(3x+4y)
Implicit Derivative d2ydx2 of dydx=3cos(3x+4y)1−4cos(3x+4y):3(−3sin(3x+4y)−4sin(3x+4y)dydx)(1−4cos(3x+4y))2