invers ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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(x+3)²25 −(y−4)²9 =1

Solution

(h, k)=(−3, 4), a=5, b=3

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(x+3)²25 −(y−4)²9 =1

Hyperbola standard equation

(x−h)²a² −(y−k)²b² =1 is the standard equation for a right-left facing hyperbola
with center (h, k), semi-axis a and semi-conjugate-axis b.

Rewrite (x+3)²25 −(y−4)²9 =1 in the form of a standard hyperbola equation

(x−(−3))²5² −(y−4)²3² =1

Therefore Hyperbola properties are:

(h, k)=(−3, 4), a=5, b=3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

invers ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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