invers 20((x-3)(x+4))/((x-3)^2(x-5))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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sin(x)+sin(x2 )=0, 0≤ x≤ 2π

Solution

x=2π, x=0, x=4π3

Degrees

x=360^◦, x=0^◦, x=240^◦

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Solution steps

One step at a time

sin(x)+sin(x2 )=0, 0≤ x≤ 2π

Rewrite using trig identities

2cos(x4 )sin(3x4 )=0

Solving each part separately

cos(x4 )=0 or sin(3x4 )=0

cos(x4 )=0, 0≤ x≤ 2π : x=2π

sin(3x4 )=0, 0≤ x≤ 2π : x=0, x=4π3

Combine all the solutions

x=2π, x=0, x=4π3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

invers 20((x-3)(x+4))/((x-3)^2(x-5))

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