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inverse (
1
2
3
4
6
9
3
7
1
)
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Solution
(
−3
1
0
2319
−819
319
1019
−119
−219
)
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Solution steps
Solve by:
One step at a time
(
1
2
3
4
6
9
3
7
1
)−1
Inverse matrix
A matrix is invertible if and only if there is a sequence of elementary row (or column) operations taking it to the identity matrix.
Augment with a 3x3identity matrix
[
1
2
3
∣
1
0
0
4
6
9
∣
0
1
0
3
7
1
∣
0
0
1
]
Reduce the matrix on the left to the identity matrix
[
1
0
0
∣
−3
1
0
0
1
0
∣
2319
−819
319
0
0
1
∣
1019
−119
−219
]
The inverse matrix is on the right side of the augmented matrix