inverse of laplace transformation xcos(2x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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inverse laplace 23−4x

Solution

−12 e^3t4

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Solution steps

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L⁻¹{23−4x }

=L⁻¹{−12 · 1x−34 }

Use the constant multiplication property of Inverse Laplace Transform:
For function f(t) and constant a: L⁻¹{a·f(t)}=a·L⁻¹{f(t)}

=−12 L⁻¹{1x−34 }

Use Inverse Laplace Transform table: L⁻¹{1s−a }=e^at

L⁻¹{1x−34 }=e^3t4

=−12 e^3t4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of laplace transformation xcos(2x)

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