next term a_{n+1}=-3a_{n},a_{1}=8

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify solve for inverse tangent line

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next term a_n+1=−3a_n, a₁=8

Solution

a₂=−24

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a₁=8, a_n+1=−3a_n

Find the sequence type for a₁=8, a_n+1=−3a_n: geometric sequence: r=−3, a_n=8(−3)ⁿ⁻¹

The last given term was a₁

Find the next term: a₂=−24

a₂=−24

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sequence type a_n+1=−3a_n, a₁=8

first term a_n+1=−3a_n, a₁=8

nth term a_n+1=−3a_n, a₁=8

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

next term a_{n+1}=-3a_{n},a_{1}=8

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