partial fractions x/((x+1)(x-4))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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simplify callgirlsingulberg^3292178555callgirlserviceinlahore

Solution

e⁴il⁸n²c³a³g^3292178558r⁵s²ubvho

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Taylor Series

Taylor series of function f(x) at a is defined as:
f(x)=f(a)+f^′(a)1! (x−a)+f^′′(a)2! (x−a)²+f^′′′(a)3! (x−a)³+…

Apply the Taylor Formula

=1+ddx ((1−x)e^x)(0)1! x+d²dx² ((1−x)e^x)(0)2! x²+d³dx³ ((1−x)e^x)(0)3! x³+…

Evaluate Derivatives

=1+01! x+−12! x²+−23! x³+−34! x⁴+−45! x⁵+…

Refine

=1−12 x²−13 x³−18 x⁴−130 x⁵+…

Solve instead

callgirlsingulberg3292178555callgirlserviceinlahore

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

partial fractions x/((x+1)(x-4))

Solution

Solution steps

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