partial fractions integral from 0 to 1 of (32)/(x^2-64)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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d⁴dx⁴ (x−2x−3 )

Solution

24(x−3)⁵

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Solution steps

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d⁴dx⁴ (x−2x−3 )

ddx (x−2x−3 )=−1(x−3)²

=d³dx³ (−1(x−3)² )

ddx (−1(x−3)² )=2(x−3)³

=d²dx² (2(x−3)³ )

ddx (2(x−3)³ )=−6(x−3)⁴

=ddx (−6(x−3)⁴ )

ddx (−6(x−3)⁴ )=24(x−3)⁵

=24(x−3)⁵

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

partial fractions integral from 0 to 1 of (32)/(x^2-64)

Solution

Solution steps

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