periodicità 2cos^3(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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polar to cartesian (−4, 2π3 )

Solution

(2, −2√3)

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Solution steps

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Definition

To convert Polar coordinates (r, θ) to Cartesian coordinates (x, y) apply:
x=r·cos(θ) y=r·sin(θ)

r=−4

θ=2π3

x=r·cos(θ)

x=−4cos(2π3 )

−4cos(2π3 )=2

x=2

y=r·sin(θ)

y=−4sin(2π3 )

−4sin(2π3 )=−2√3

y=−2√3

The Cartesian coordinates of (−4, 2π3 )

(2, −2√3)

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

periodicità 2cos^3(x)

Solution

Solution steps

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