provar (cos(x))/(1-sin(x))=sec(x)+tan(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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implicit derivative d²ydx² , x³+y³=4

Solution

d²ydx² =−2x(x³+y³)y⁵

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e^x+e^y=1

Treat y as y(x)

Implicit Derivative dydx of e^x+e^y=1: −e^x−y

dydx =−e^x−y

Implicit Derivative d²ydx² of dydx =−e^x−y: −e^x−y(1−dydx )

d²ydx² =−e^x−y(1−dydx )

Substitute dydx =−e^x−y: −e^x−y(1+e^x−y)

d²ydx² =−e^x−y(1+e^x−y)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

provar (cos(x))/(1-sin(x))=sec(x)+tan(x)

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