prove (tan^2(x)-1)/(sec^2(x))=(tan(x)-cot(x))/(tan(x)+cot(x))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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√☐

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log_□

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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prove tan²(x)−1sec²(x) =tan(x)−cot(x)tan(x)+cot(x)

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tan²(x)−1sec²(x) =tan(x)−cot(x)tan(x)+cot(x)

Manipulating left side

tan²(x)−1sec²(x)

Express with sin, cos

=−cos²(x)+sin²(x)

Manipulating right side

tan(x)−cot(x)tan(x)+cot(x)

Express with sin, cos

=−cos²(x)+sin²(x)cos²(x)+sin²(x)

Rewrite using trig identities

=−cos²(x)+sin²(x)

We showed that the two sides could take the same form

⇒ True

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+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
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prove (tan^2(x)-1)/(sec^2(x))=(tan(x)-cot(x))/(tan(x)+cot(x))

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