prove cot(x)+tan(x)=sec(x)csc(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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prove cot(x)+tan(x)=sec(x)csc(x)

Solution

True

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Solution steps

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cot(x)+tan(x)=sec(x)csc(x)

Manipulating left side

cot(x)+tan(x)

Express with sin, cos

=cos²(x)+sin²(x)cos(x)sin(x)

Rewrite using trig identities

=1cos(x)sin(x)

Rewrite using trig identities

sec(x)csc(x)

We showed that the two sides could take the same form

⇒ True

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+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

prove cot(x)+tan(x)=sec(x)csc(x)

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