rango x^{2/3}(2x-1)

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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range x²³(2x−1)

Solution

f(x)>−1· 2(−1)²³·∞

Interval Notation

(−1· 2(−1)²³·∞ , ∞ )

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Function range definition

The set of values of the dependent variable for which a function is defined

Find the minimum and maximum value in each defined interval and unite the results

Domain of x²³(2x−1) : −∞ <x<∞

Extreme Points of x²³(2x−1): Maximum(0, 0), Minimum(15 , −35· 5²³ )

Find the range for the interval −∞ <x<∞ : −1· 2(−1)²³· ∞ <f(x)<∞

Combine the ranges of all domain intervals to obtain the function range

f(x)>−1· 2(−1)²³· ∞

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domain x²³(2x−1)

intercepts x²³(2x−1)

parity x²³(2x−1)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

rango x^{2/3}(2x-1)

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