sequence type a_{1}=-2,d=3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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sequence type a₁=−2, d=3

Solution

arithmetic sequence: d=3, a_n=3n−5

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Solution steps

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a₁=−2, d=3

The n-th term of an arithmetic sequence is of the form a_n=a₁+(n−1)d

a₁=−2, d=3

a_n=−2+(n−1)· 3

Simplify −2+(n−1)· 3: 3n−5

arithmetic sequence: d=3, a_n=3n−5

Solve instead

first term a₁=−2, d=3

nth term a₁=−2, d=3

next term a₁=−2, d=3

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sequence type a_{1}=-2,d=3

Solution

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