sin^2

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify solve for inverse tangent line

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f(x)=sin²(x)

Solution

Period: π

Domain: −∞ <x<∞

Range: 0≤ f(x)≤ 1

X Intercepts: (πn, 0), Y Intercepts: (0, 0)

Asymptotes: None

Extreme Points: Minimum(πn, 0), Maximum(π2 +πn, 1)

Interval Notation

Domain: (−∞ , ∞ )

Range: [0, 1]

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Periodicity of sin²(x): π

Domain of sin²(x) : −∞ <x<∞

Range of sin²(x): 0≤ f(x)≤ 1

Axis interception points of sin²(x): X Intercepts: (πn, 0), Y Intercepts: (0, 0)

Asymptotes of sin²(x): None

Extreme Points of sin²(x): Minimum(πn, 0), Maximum(π2 +πn, 1)

Solve instead

ddx (sin²(x))

∫ sin²(x)dx

inverse sin²(x)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sin^2

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