solve by complete the square x^2+6x+8=0

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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f(x)=log₄(4x)

Solution

Domain: x>0

Range: −∞ <f(x)<∞

X Intercepts: (14 , 0)

Asymptotes: Vertical x=0

Extreme Points: None

Interval Notation

Domain: (0, ∞ )

Range: (−∞ , ∞ )

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Solution steps

One step at a time

Domain of log₂(2x) : x>0

Range of log₂(2x): −∞ <f(x)<∞

Axis interception points of log₂(2x): X Intercepts: (12 , 0)

Asymptotes of log₂(2x): Vertical: x=0

Extreme Points of log₂(2x): None

Solve instead

ddx (log₄(4x))

inverse log₄(4x)

parity log₄(4x)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

solve by complete the square x^2+6x+8=0

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