solve by complete the square x^2-6x+9=25

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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□□

log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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x²−6x+9=25

Solution

x=8, x=−2

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Solve by:

Completing the square

Quadratic formula

Factoring method

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x²−6x+9=25

Move 9 to the right side

x²−6x=16

Rewrite in the form (x+a)²=b

(x−3)²=25

For f ²(x)=a the solutions are f(x)=√a, −√a

Solve x−3=√25: x=8

Solve x−3=−√25: x=−2

The solutions to the quadratic equation are:

x=8, x=−2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

solve by complete the square x^2-6x+9=25

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