solve by factoring 5x^2-8x+3=0

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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3x²+2x−8=0

Solution

x=43 , x=−2

Decimal

x=1.33333…, x=−2

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Factoring method

Quadratic formula

Completing the square

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3x²+2x−8=0

Factor 3x²+2x−8: (3x−4)(x+2)

(3x−4)(x+2)=0

Using the Zero Factor Principle: If ab=0 then a=0 or b=0

3x−4=0 or x+2=0

Solve 3x−4=0: x=43

Solve x+2=0: x=−2

The solutions to the quadratic equation are:

x=43 , x=−2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

solve by factoring 5x^2-8x+3=0

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