solve by quadratic formula (z^2)/6-(3z)/2-6=0

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z²6 −3z2 −6=0

Solution

z=12, z=−3

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Solve by:

Quadratic formula

Completing the square

Factoring method

One step at a time

z²6 −3z2 −6=0

Find Least Common Multiplier of 6, 2: 6

Multiply by LCM=6

z²6 · 6−3z2 · 6−6· 6=0· 6

Simplify

z²−9z−36=0

Solve with the quadratic formula

z_{1, 2}=−(−9)± √(−9)²−4· 1· (−36)2· 1

√(−9)²−4· 1· (−36)=15

z_{1, 2}=−(−9)± 152· 1

Separate the solutions

z₁=−(−9)+152· 1 , z₂=−(−9)−152· 1

z=−(−9)+152· 1 : 12

z=−(−9)−152· 1 : −3

The solutions to the quadratic equation are:

z=12, z=−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
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solve by quadratic formula (z^2)/6-(3z)/2-6=0

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